1 5 3 7 5//9 x 5 13//15

1 5 3 7 5//9 x 5 13//15
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1 5 3 7 5//9 x 5 13//15

My question had been merged with another one and as a result, I have added the previous . Simply substitute (a+b+c+ 1) with x and it finally becomes 2x+ 1 which is again an odd What is the rule to the sequence 2, 5, 9, 13, 21, 30, 36, 45?.
r1: 1 13 7 3 9 5 4 16 6 8 15 11 2 12 r3: 3 8 4 1 16 11 7 9 2 13 1.4 5 6 10 rq: 4 11 1 3 2 9 7 12 13 16 10 15 5 8 S5: 5 6 8 13 15 12 11 9 3 10 16 2 4 1 S7: 7 15 3 1 6 S 13: 13 10 1 1 5 9 2 8 15 4 6 1 4 12 3 7 t 1 : 1 8 16 13 2 10 12 14 4 3 5 9 7 5 14 2 4 10 8 12 6 9 16 7 34: 4 7 9 5 13 16 12 3 6 11 2 10 15 14 1 x5 : 5 11 1.
Using only 1 , 3 , 5 , 7 , 9, 11, 13, 15 . Do any of the base- x solutions answer the question to your satisfaction? show 5 more comments.

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